Solution: because the straight line p passes through the origin, let the straight line P: Y = AX.
Convert the straight line L into: y=3x+ 1/2 Slope k=3.
The straight line p is parallel to the straight line l, that is, the slope a of the straight line p is equal to the slope k: 3 of the straight line l,
So the straight line p: y = 3x
2. ABCD is known to be a parallelogram. A (1, 6), B (9 9,2), C (9 9,0), D (1, 4), 1) find the corresponding point reflected by point d on y=2. 2) Find the parallelogram ABCD.
Solution: 1) The corresponding point D'( 1, 0) 2)order2 does not understand.
3. A (-7, 1), B (3 3,6) and C (1, 4) are known.
A) suppose that b is the midpoint of AX, and find the point coordinates of x.
Solution: Let the straight line where AX is located be y=kx+b, and substitute the A and B coordinates to get the equation as y= 1/2x+9/2.
The distance between A and B on the X axis is 10, and B is the midpoint of AX, so the distance between B and X on the X axis is also 10, and x( 13, 1 1) is obtained.
4. Given A (-2,7), B (-2,2) and c (6 6,4), find the value of sin < ABC.
Solution:
Sin & ltABC= two thirds root number three
5. Points A (-5,5), B (1 3) and C (4 4,3) are shown in the figure.
a)。 Find the straight line equation that passes through the point (0,3) and is parallel to the straight line AB;
b)。 Looking for cos
Solution: a). The equation for finding straight line AB: y=-4/3x-5/3.
The parallel slopes of straight line L and straight line AB are the same. Y =-4/3x+B. Substitute point (0,3) to get b=3.
That is, y=-4/3x+3.
b)。 & lt drawings ABC = 120 can be obtained.
cos & ltABC=- 1/2