∫S△ABC = BC×ad÷2 = ab×ce÷2，

∴BC/AB=CE/AD=8/6=4/3，

Let BC=4x, then AB=AC=3x,

∵AD⊥BC，

∴BD=CD=2x (three lines in one),

According to pythagorean theorem AB 2-BD 2 = AD 2,

That is, (3x) 2-(2x) = 6 2

x=6√5/5，

AB=AC= 18√5/5

BC=24√5/5，

△ circumference of △ABC =AB+AC+BC= 12√5 (cm).