SSA is not established because the angle A is fixed on one side AB, and the other vertex B on this side is the center of the circle. There may be two intersections between circle B and angle A on the other side, forming two triangles, an obtuse angle and an acute angle (or only one intersection, in this case a right angle). These two triangles intersect with SSA, but they are not equal. You can't draw pictures here, so the landlord will discuss it again:) If both triangles are defined as acute angles or obtuse angles,
In addition, when two triangles are known to be acute or obtuse, they can be made high and proved to be congruent by two congruences.
I don't know if I made it clear. The landlord had better draw a picture himself and think about it again. I wish you a happy study!