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Three mathematical problems
Solution: The least common multiple of (1)3 and 4 is 12. When each number reaches 12, 1, 2, 3 * * are the same. There are 8 100 12, and so are the remaining 4.

(2) At least 102 capsules.

The least common multiple of 3 and 5 is 15, 15 divided by 7 and 1. If there are 4 grains left in the distribution of 7 grains, it should be 15× 4. The least common multiple of 3 and 7 is 2 1, and the remainder of 2 1 divided by 5 is 1. If there are 2 grains left in the distribution of 5 grains, it should satisfy 2 1×2, and then it should be divisible according to the distribution of 3 grains, that is to say, it is a multiple of 3, and each number in front is a multiple of 3, and 15× 2.

(3) 12 line No.21,Huanhuan gotNoB is in line A, then a * b = 84× 3 = 3× 3× 2× 7 = 2/kloc-0 /×12.

Because a≤20, a = 12. Then b = 2 1. That is, the number of line 12 is 2 1.