We might as well set the number of saplings as x, and after calculating the number of saplings, we can list the equation through this equation because the number of saplings taken in each class is the same.

Well, the number of saplings taken in the first class is100+(x-100)/10. So now all that's left is.

X-100+(x-100)/10 seedlings. So the number of saplings taken by the second class is

200+{ X-200- 100+(X- 100)/ 10 }/ 10。 Because the number of saplings in each class is equal, so:

100+(x- 100)/ 10 = 200+{ x-200- 100+(x- 100)/ 10 }/ 10

The solution is x=8 100.

So in the first class,100+(8100-100)/10 = 900 seedlings, that is, 900 seedlings were taken in each class, so * * has 8100/900.

Well, the key to this kind of problem is to find the equivalence relation, and the equivalence relation can be obtained by representing other unknowns with unknowns. Oh, you seem to have typed a lot of words wrong. Oh, don't be in such a hurry, okay? Ha ha. You are in Grade One, aren't you? Learn math well in junior high school. When you get to senior high school, you will find that math in junior high school is really simple.