When the velocity of the metal bar at moments A and T is v=at and the induced electromotive force is E=BLv=BLat, it is known that E∝t and E-t images should be inclined straight lines passing through the origin, so A is wrong.

B, according to the induced charge formula q = △φ r = blxr = bl? 12at 2r∝T2； Q-t is like a parabola with an upward opening, so b is correct.

C, the power consumed by the resistor r p = e2r = (blat) 2r ∝ t2; P-t is like a parabola with an upward opening, so c is wrong.

D according to Newton's second law: F-F an =ma, f an =B2L2vR=B2L2atR, simultaneous: F=B2L2atR+ma. According to mathematical knowledge, F-t looks like a straight line that inclines upward, so D is correct.

So: BD.