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Junior high school outdoor mathematics
Application questions:

1: For simplicity, remember that A stands for freight car and B stands for passenger car. With the front of the car aligned, B overtook A in 24 seconds, which means that A and B*** are driving together when they are not overtaking, but B runs fast, so A can be regarded as stationary, and B runs at a speed of (32-25)=7 (meters) per second, which takes 24 seconds.

2. Similar problem 1, A runs 20 times faster than B, and the runway is 400. The first time A caught up with B, A ran one lap more than B, so the time was 400/20=20 (minutes). When A catches up with B for the first time, it starts to run at the same time, but at this time, A and B run for 20 minutes each, but when A catches up with B for the second time, it will still run for another 20 minutes, and the third time it will still be 20 minutes. So running 60 divided by 400/ 120 is equal to 18 (circle), and the second circle is 400/ 100=4 (minute), so running 15 (circle).

3: If the length of thick rope is x meters, the length of a circle is (x- 10) divided by 14, which is equal to (x- 10)/ 14 (meters), and 2 1 circle length is 2/kloc.

8*(x-3*(x- 10)/2)=x, solve it,

8x- 12*(x- 10)=x

8x- 12x+ 120=x

5x= 120

X=24 meters