Please put 15 apples in four boxes, so no matter how many apples you want to take, you don't need to open the box, just take one or more. Then, among the four boxes, the box with the most apples has 88 apples.

Test sites: numbers and questions.

According to the meaning of the question, one box should hold the most, and the other three boxes should hold the least. You can think of 15 as the sum of four different addends, at least put 1, and then put two boxes, so there are three, so there are four more boxes in the box and eight in the last box, so 15 = 65438+.

Solution: According to the meaning of the question, one box is required to hold the most, and the other three boxes should hold the least, at least 1.

Put 1 in a box and two in a box. 1 and 2 are equal to three.

So put four in the third box and eight in the last box, which is 15= 1+2+4+8.

No matter how many apples you take, you don't have to open the box when you first take them.

So there are eight apples in the most box.

So the answer is: 8.

Comments: To solve this problem, we should pay attention to "the number of apples is different from each other" and that no matter how many apples we take, we don't need to unpack them. We can treat them as the sum of several different addends to analyze and answer them.