0 2 4 6 8 or 2 4 6 8 10
Considering that the total number of games is C (5,2) 2)= 10/0,
In the case of a draw, each team has a total score of 2 and the winner is 3.
If the score of each team is 2 4 6 8 10, the total score is 30. This score will only be generated if all the matches of 10 are decided and there is a draw in the question. Obviously, this contradicts the meaning of the question, and the score can be obtained as 0.2468.
Let each team rank according to the order from small to large (where B is Team A):
a b c d e
0 2 4 6 8
At this time, it can be determined that Team E has 2 wins and 2 draws, and Team B has 2 draws.
The total score of each team is 0+2+4+6+8=20.
If there is a draw in a single game, the cumulative score of all games is 3n- 1 (that is, the total score of a draw is one point less than that of the deciding game). If there are x draws in * * *, the total score is 3n-x(x is the number of draws).
20 = 3*7- 1 = 3*8-4 = 3*9-7
It is known that there are at least two draws, and 3*7- 1 is excluded.
If the number of tied games is 7, the sum of tied game points is 14, and the winning and losing game points are 20- 14=6.
Only Team E won, and Team D drew 6, but each team can only play 4 games at most, which contradicts the problem. Seven draws are impossible, so the number of draws is four.
The number of tie games is 4, and the sum of points of tie games is 8. Team B (A) and Team E each scored 4 points, and the remaining 4 points were distributed to Team C (4 points) and Team D (6 points).
Team C's 4 points can't be equally divided, because in that case, Team A will have at least 1 point.
Then Team C should be 1 win 1 draw. If the sum of the tie points of Team C and Team D is 4, then Team D is 1 win and 3 draw.
The integral is as follows:
a b c d e
Integer 0 2 4 6 8
Sheng 1 1 2
Ping 2 1 3 2
negative
Then the number of D draws is 3, namely bd, cd and ed, and the rest are bd.
That is, team a and team d, team e tied and lost only to team c, that is, team B.
Conclusion: Team B scored 4 points.