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High school mathematics real number
k & gt= 1

The following is the answer process:

pq=kmn

p+q=k(m+n),

There is a positive real number pq, which is equivalent to the discriminant (p-q)? =k? (m+n)? -4 kmn & gt; =0。

K is obviously greater than 0, so the above formula is equivalent to k & gt=4mn/(m+n)? =4/(m/n+n/m+2)

This formula needs to hold for all MnS, so we only look at the maximum value of 4/(m/n+n/m+2).

m/n+n/m & gt; =2√(m/n*n/m)=2, so 4/(m/n+n/m+2)

Therefore, k>= 1.