V water = SH = 2×10-2m2× 0.1m = 2×10-3m3,

∑ρ= mV，

∴m water = rho water v water =1.0×103kg/m3× 2×10-3m3 = 2kg;

(2)p water = rho water gh water =1.0×103kg/m3× 9.8n/kg× 0.1m = 980pa;

(3) Gravity of water:

G water =m water g=2kg×9.8N/kg= 19.6N,

Gravity of cylindrical container;

G container =m container g=2kg×9.8N/kg= 19.6N,

Pressure of the container on the desktop:

F=G water +G container =19.6n+19.6n = 39.2n,

Pressure of container on desktop:

p=FS=39.2N2× 10？ 2m2= 1960Pa。

Answer: (1) The mass of water in the container is 2 kg.

(2) The water pressure at the bottom of the container is 980 Pa. ..

(3) The pressure of the container on the desktop is 1960Pa. ..