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Mathematical problems of legs
The teacher only taught us to solve by equations. .

Solution: There are × cranes and (200-×) turtles.

2×-4(200-×)=76

2×-800+4× =76

6×=476

×= 146

200- 146 = 54 (only)

A: There are 54 turtles and 46 cranes/kloc-0.

A crane has two legs, a crane has two legs. A turtle has four legs, and (200-×) turtles have four (200-×) legs. The tortoise has 76 fewer legs than the crane, which is the difference in the number of legs between the tortoise and the crane. Cranes have 2× legs and turtles have 4 (200-×). All cranes have more legs than all turtles. Then use 2×4(200-×), which is equivalent to the difference of the number of legs of 76, and the equation is 2×4(200-).

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