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Narrowing reasoning in junior high school mathematics
Let AB=a, then BC=2a. Then AB = CD = EF = a; in rectangular ABCD; AD=BC=2a。 ? AE=DE=BF=CF=a

Then the circumference of rectangular ABCD is AB+BC+CD+AD=a+2a+a+2a=6a.

? The circumference of rectangular ABFE is AB+BF+EF+AE=4a.

? Rectangular ABFE perimeter =2/3? Rectangular ABCD perimeter

Perimeter of rectangular MBFN = 1/2? Rectangular ABCD perimeter

In the nth segmentation, n>3;

If n is an odd number, the perimeter of the rectangle is {6 * (2/3 * 3/4) (n-1)} * 2/3 = (1/2) (n-3).

If n is an even number, the circumference of the rectangle is 6 * (2/3 * 3/4) n = 3 * (1/2) (n-1).