Take point e on CB, let CE=CA, connect AE,

∫∠ACB = 60，

∴△ACE is positive △,

∴∠AEC=60，

∫△ACD?△ECD

∴AD=DE=BE，

Let ∠DAE=X,

So DEA = x,

∠BDE=2X，

∠DBE=2X，

∠DEC=4X，

That is ∠AEC+∠AED=60+X=4X,

The solution is x = 20.

∴∠BAC=60 +20 =80