Take point e on CB, let CE=CA, connect AE,
∫∠ACB = 60,
∴△ACE is positive △,
∴∠AEC=60,
∫△ACD?△ECD
∴AD=DE=BE,
Let ∠DAE=X,
So DEA = x,
∠BDE=2X,
∠DBE=2X,
∠DEC=4X,
That is ∠AEC+∠AED=60+X=4X,
The solution is x = 20.
∴∠BAC=60 +20 =80