Analysis: First, we can get the degree of ∠ABC according to the triangle interior angle theorem, then we can get the degree of ∠EBD according to the properties of the angle bisector, and then we can get the degrees of ∠EDB and ∠BED according to the properties of parallel lines and the triangle interior angle theorem.

Solution: In △ABC,

∠∠A = 60，∠C=80，

∴∠ABC= 180 -∠A-∠C-=40，

∫BD is the bisector of ∞∠ABC,

∴∠EBD= 1/2∠ABC=20，

∫DE∨BC，

∴∠EDB=∠DBC=20，

Then ∠ bed =180-∠ EBD-∠ EDB =180-20 =140.

Therefore, the internal angles of △BDE are: ∠ EBD = 20, ∠ EDB = 20, ∠ Bed = 140.

The fastest answer, hope to adopt, thank you.