Analysis: First, we can get the degree of ∠ABC according to the triangle interior angle theorem, then we can get the degree of ∠EBD according to the properties of the angle bisector, and then we can get the degrees of ∠EDB and ∠BED according to the properties of parallel lines and the triangle interior angle theorem.
Solution: In △ABC,
∠∠A = 60,∠C=80,
∴∠ABC= 180 -∠A-∠C-=40,
∫BD is the bisector of ∞∠ABC,
∴∠EBD= 1/2∠ABC=20,
∫DE∨BC,
∴∠EDB=∠DBC=20,
Then ∠ bed =180-∠ EBD-∠ EDB =180-20 =140.
Therefore, the internal angles of △BDE are: ∠ EBD = 20, ∠ EDB = 20, ∠ Bed = 140.
The fastest answer, hope to adopt, thank you.