max = 2 * x 1+3 * x2+4 * x3；

1.5 * x 1+3 * x2+5 * x3 & lt； =600;

280 * x 1+250 * x2+400 * x3 & lt； =60000;

@ gin(x 1)；

@ gin(x2)；

@ gin(x3)；

The running results are x 1=64, x2= 168, x3=0!

When x 1≥80 is required, just add one sentence: x1≥ 80; That's it.

The result is x 1=80, x2= 150, x3=0!

Similarly, other answers are: x 1=64, x2= 168, x3=0!

And x 1=73, x2=30, x3=80!

(# ``) convex first person

Help! ! ! ! ! ! Can you give me some advice? O(∩_∩)O~