Current location - Training Enrollment Network - Mathematics courses - Calculation problems in senior high school mathematics entrance examination
Calculation problems in senior high school mathematics entrance examination
The simplest way to solve this problem is to add equations by Pythagorean theorem.

Solution: ∵ABCD is rectangular.

∴∠A=∠D=∠ABC=∠DCB

∴△ APB and△ PDC are right triangles.

∫△PHF is a right triangle.

∴△ APB, △ PDC and △ PHF are all right triangles.

Let AP be x, then PD =10-X.

∴BP? =X? +4? ,PC? =( 10-X)? +4?

BC? = 10? = 100

△ PBC is a right triangle.

∴X? +4? +( 10-X)? +4? = 100

∴X? - 10X+ 16=0

∴X? - 10X+25-25+ 16=0

∴(X-5)? =9

∴X-5= 3

X = 8 or 2

A: Yes, the AP length is 8 or 2.