∵M is the midpoint of A'B'

∴MC=B'M= 10/2=5

NC=6/2=3

∴MN^2=5^2 - 3^2

MN=4

AN=8+3= 1 1

∴am=4^2+ 1 1^2 =√ 137

In addition, if there is, the auxiliary line is the same.

∴AM=4^2+5^2 =√4 1

2)∫OD = OP∠DOP = 60

∴△DOP is an equilateral triangle

∠∠COP+∠AOP = 120∠AOP+∠OPA = 120。

∴∠COD=∠OPA

∠ C =∠ A = 60。

∴△COD≌△AOP

∴AP=CO=6