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Senior 1 Math 2 (50 points of satisfaction)
The sum of three natural numbers is exactly 13, and the middle number must be the middle value, that is,1144/13 = 88, so the answer is1144 = 82+83+.

Since it was 33 times in previous years, we only need to use the ergodic method to calculate the integer times of 33, and the integer times of 33 after 1900 (year) are only 19 14, 1947, 1980.

If1914 = 33 * 581947 = 33 * 591980 = 33 * 60, the year is1914+58 =. According to the language environment in China, it is impossible to say that 1972 was a few years ago, so this year is 2006, and Mr. Zheng was born in 1947.

Because I can't write clearly, if I can't write a square in the formula, I will write XX, which means a square, and XXX means a cube. However, since you answered, do it. I came up with a clever idea. This is a fill-in-the-blank question, so as long as the result is correct, we might as well use the most convenient number to generate this XYZ. Of course, we have to make your premise stand. X=Y=Z=0 can make the equation hold without affecting the next expression (denominator is not 0), so the answer is (1+1+)/(1+1) = 65438.

This method is a test of pure computing power. Just expand the formula, that is, (x-2) (xx-2x+4)-x (x-3)+(2x-1) (2x-1) =13x-7.

God, this question, ... however, seems unnecessary. Because187 x-104y = 41104y is an even number, that is to say, a number minus the even number equals the odd number. Obviously, x must be singular, which means only (3 14.

Is this the topic of senior one? My daughter is going to junior high school soon. If it's so difficult, I'm afraid her mother can't teach at home alone. ....

Oh, after typing these, I saw that there was already such an answer above. They type quickly. ......