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The answer to a math problem
E is to cut the length into two small rectangles in half, and the circumference of the small rectangle is (1/2+ the width of the large rectangle) ×2.

Therefore, the length of a big rectangle is 1/2+ width = 40 ÷ 2 = 20cm-( 1).

F is to fold the width in half and cut it into two small rectangles. The circumference of a small rectangle is (the length of a large rectangle+the width of 65438 +0/2)×2.

Therefore, the length of the big rectangle+the width of the big rectangle 1/2 = 50 ÷ 2 = 25 cm-(2).

Add (1) and (2) to the left, and add right to the right to get it.

A large rectangle with length ×3/2+ width ×3/2=45CM.

Length+width = 30 cm

The circumference of the rectangle is 30×2=60 (cm).