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The problem of sine and cosine theorem in high school mathematics
solve

(a? +b? -c? )/(a+b-c)=c?

Answer? +b? -c? =(a+b-c)c? =(a+b)c? -c?

Answer? +b? =(a+b)c?

(a+b)c? =a? +b? =(a+b)(a? -ab+b? )

c? =a? -ab+b?

Answer? +b? -c? =ab

(a? +b? -c? )/(2ab)= 1/2

Combined with cosine theorem: cosC=(a? +b? -c? )/(2ab)= 1/2

Merge 0 again? < C< 180? Available: C=60?

A+B= 120?

3/4 = Sina sinb =( 1/2)[cos(A-B)-cos(A+B)]

3/2=cos(A-B)-cos 120? =cos(A-B)+( 1/2)

∴cos(A-B)= 1

Combination-120? < A-B< 120? Yes: A=B=60?

A triangle is an equilateral triangle.