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Shadow area in sixth grade mathematics
First of all, this graph consists of a 1/4 circle with radius of 2 and a triangle with right angles of 2 and 3.

The area of 1/4 circle is 1/4*π*4=π=3. 14.

The area of the triangle is 1/2*2*3=3.

The unshaded figure is also a triangle, with one side being 2 and the height being 2. Because the unshaded figure is an obtuse triangle and one of its vertices is also a vertex of the right triangle, its height is equal to that of the right triangle, which is 2, and the area of the unshaded figure is 1/2*2*2=2.

So the shadow area is 3. 14+3-2=4. 14.