Assume that the number of male white, black, flower and brown cattle is X 1, X2, X3 and X4 respectively, and the number of female white, black, flower and brown cattle is Y 1, Y2, Y3 and Y4 respectively.

x 1=x4+5/6*x2

x2=x4+9/20*x3

x3=x4+ 13/42*x 1

y 1=7/ 12*(x2+y2)

y2=9/20*(x3+y3)

y3= 1 1/30*(x4+y4)

y4 = 13/42 *(x 1+y 1)

After completing the simplification, you get

x 1=5936/2376*x4

x2= 178/99*x4

x3= 1580/89 1*x4

y 1 = 2402 120/ 1383 129 * x4

y2=543694/46 1043*x4

y3 = 3709 10 1600773436857/4377498837804 122 1 12 * x4

y4 = 7364065427525072 19 19/56 17790 175 18 19567 104 * x4

Because the number of cattle must be an integer, so? x4 = 56 17790 175 18 19567 104 * K？ (K= 1, 2, 3, ...), take K= 1 and get a set of solutions:

x 1 = 140350 178787374 137344

x2 = 10 1006732442665484288

x3 = 996 1962375743537 1520

x4 = 56 17790 175 18 19567 104

y 1 = 9756578 1 178820502702

y2 = 662488924353 125 13234

y3 = 47600 1372099257720 10

y4 = 7364065427525072 19 19

The figure at the back is too big, which is calculated by the computer. I really admire Archimedes' hand-calculated results. Cows are cows! However, the sun god has many cows, probably more than the stars in the solar system!