∫A = 3p, A is a multiple of 3, but the sum of the numbers of A is equal to the sum of the numbers of P,
From the divisible discrimination method, we know that p is a multiple of 3.
∴p=3m, (m is a positive integer),
∴a=3×p=3×3m=9m,
∴a is divisible by 9.
The sum of the numbers of ∫A is equal to the sum of the numbers of P,
∴ According to the discrimination method of divisibility by 9, p can be divisible by 9, that is, p=9k(k is an integer).
∴p=3a=3×9k=27k
∴a is a multiple of 27.
∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴∴875
∫a and B are both "hope numbers",
∴a and B are multiples of 27, that is, a=27n 1 and b=27n2(n 1, n2 is a positive integer).
∴ab=(27n 1)(27n2)
=(27×27)(n 1×n2)
=729n 1n2。
∴ab must be a multiple of 729.