When 3 n is n∈N*, its unit digits are 3, 9, 7, 1, 3, 9, 7, 1, …;

When 4 n is n∈N*, its unit digits are 4, 6, 4, 6, 4, 6, 4, 6, ...;

∴ 3 n+4 n When n∈N*, the unit number is 7,5, 1, 7,5, 1, 7, ...

To make (3 n+4 n)/5 a positive integer,

Then n = 2,6, 10, 14,

That is n=4k-2, k∈N*.

∴ Set A={n| n=4k-2, k∈N*}.

At this time, set A is the set of all positive integers divided by 4 and 2.

It can be expressed by enumeration as {2,6, 10, 14,18,22,26, …};

Set B={x|x=(2k- 1)? + 1，k∈N*}

={x|x=4k？ -4k+2，k∈N*}

={x|x=4k(k- 1)+2，k∈N*}。

When k∈N*, k(k- 1) takes 0, 2, 6, 12, 20,

∴ Set B can be expressed as {2, 10, 26, 50, 82, ...} through enumeration;

To sum up, set B is the proper subset of set A. 。