x= 1+t/2

y=√3t/2

Substituting it into the parametric equation of curve C, we get

1+t/2=cosθ

√3t/2=sinθ

( 1+t/2)？ +(√3t/2)？ = 1

t？ +t=0

Then t=0, t=- 1.

(1) intersection coordinates (1, 0) and (1/2, -√3/2).

(2) The slope of 2)OA line is 1/tanα.

The linear equation of OA is y=x/tanα.

The equation of the straight line l is: y=tanα x+ 1.

Coordinates of intersection p:

x = 1/( 1/tanα-tanα)= tanα( 1-tan？ α)/

y= 1/( 1-tan？ α)