According to the nature of the center of gravity: G is the center of gravity, then GA:GD=2: 1.

The center of gravity is the intersection of the middle lines, so the intersection of AG and BC is the midpoint of the side, that is, D is the midpoint of BC.

Because O is the outer center, the outer center is the intersection point of the middle vertical line, and D is the midpoint of BC, so OD⊥BC.

H is human, so? AE⊥BC。 So OD//AE has ∠ODA=∠EAD.

Connecting CG and extending the intersection of BA and F, we can know that F is the midpoint of AB. Similarly, the //CM. So there is ∠OFC=∠MCF? Connect FD, FD parallel AC, DF:AC= 1:2. FD and AC are connected in parallel, so ∠DFC=∠FCA, ∠FDA=∠CAD, and ∠OFC=∠MCF, ∠ODA=∠EAD, subtraction can get ∠ OFD = ∠. GA:GD=2: 1, so OD:HA=GA:GD=2: 1.

And ∠ODA=∠EAD, so △OGD∽△HGA.

So: OD=GA:GD,

GA:GD=2: 1，

So: OD=2: 1,