We assume that the analytical formula of the straight line BE is y=x+b, because it is parallel to (y=x, so the value of k is the same), and it can find out that b=-2 by substituting the point e (2 2,0) into the analytical formula, so y=x-2.

Below is an auxiliary line, the intersection point A is AD, the vertical Y axis is D, and the straight line AC intersecting with the X axis is F.

Then the area of quadrilateral AOEC = the area of trapezoid DOFA-the area of triangle ADO-the area of triangle CEF.

Because the ordinate of point C is 1, if you substitute y=x-2, the coordinate of point C is (3 1).

So the analytic expression of hyperbola is y = 3/x.

Point A is the intersection of curve y=3/x and straight line Y = x. By establishing the equation, the coordinate of point A is (root number 3, root number 3).

Then, the analytical formula of straight line AC and its intersection with x axis is obtained.

Y=- root number 3/3+ 1+ root number 3 The coordinate of point F is (3+ root number 3,0).

This area can be found below.

Area of quadrilateral AOEC = area of trapezoid DOFA-area of triangle ADO-area of triangle CEF.

=(DA+OF)* OD/2-AD * CD/2-EF * 1/2

= (radical number 3+3+ radical number 3)* radical number 3/2- radical number 3* radical number 3/2-(3+ radical number 3-2)* 1/2

= 1+ root number 3

The function problem is too complicated. Remember to hang up more so that more people will be willing to help.