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Century Jinbang Mathematics High School Compulsory One
The original formula of the first question = 3lg (x/2)-3lg (y/2) = 3 [(lgx-lg2)-(lgy-lg2)] = 3 (lgx-lgy) = 3a.

I was puzzled at the beginning of the second question, but you can see the formula you wrote next to the third option. The loga(x) power of A you wrote is equal to X, but you pay attention to the formula on your right. That is, loga(x) of x equals x, and how many times of x equals x is obviously 1, but loga(x) does not necessarily satisfy the equation of 65438+.

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