∴? k+b= 1？ 7k+b = 0，k = 7+ 16b = 7+76。
The analytical formula of ∴ straight line is: y=7+ 16x+7+76,
∫-x > kx+b > 0，
∴ 0 < 7+ 16x+7+76
Solution 2:∫A(- 1, 1) and B (-7,0),
∴ According to the function image, when x >-7, the straight line is above the X axis, that is, KX+B > 0.
When -7 < x kx+b > 0 holds.
So the answer is: -7 < x