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Can you help me solve the following two fifth-grade math problems?
The sum of the numerator and denominator of a fraction is 7 1. If 1 is added to the molecule, it can be reduced to two-sevenths of the simplest fraction. The original score was ().

Let the numerator be X, then the denominator is 71-X.

Then (x+ 1)/(7 1-x)=2/7.

Then 2*(7 1-x)=7*(x+ 1)

Extension 142-2x=7x+7

9x= 135

X= 15 is 7 1- 15=56.

The original score is 15/56.

The fractional numerator plus 1 is three fifths, and the denominator minus 1 is four sevenths. What is the score?

Solution: let this score be a/b.

Then (a+ 1)/b=3/5.

a/(b- 1)=4/7

If a=32, then b=55.

The score is 32/55.