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Excuse me, how to buy a ticket for the following two math problems?
1, 6 adults and 4 children, how to buy a ticket is cost-effective.

Scheme 1, adult 150 yuan, child 60 yuan150 * 6+60 * 4 =1140.

Option 2: each group with more than 5 people 100 yuan100 *10 =1000.

Scheme 3 (6 adults: group)+1 adult +4 children 100*6+60*4=840.

Scheme 3 is superior to Scheme 2 and Scheme 1.

There are four adults and six children. How to buy a ticket is the most economical?

Scheme 1: adults 150 yuan, children 150*4+60*6=960.

Scheme 2: For groups with more than 5 people (including 5 people), each person 100 yuan100 *10 =1000.

Scheme 3 (4 adults+1 child: group) +5 children 100*5+60*5=800.

Scheme 3 is superior to scheme 1 and scheme 2.