Suppose there are x students and X/ 12 teachers, then a * * * is 20X+(X/ 12)*40, which is 20X+ 10X/3 yuan.
Let an angle be X, then its complementary angle is180-X. According to the meaning of the question: X = 3 (180-X)+10, X = 137.5 is calculated, so the size of the angle is/kloc-0.
13.AB passes through the parallel line GH of c and EF passes through the parallel line IK of d.
From AB//GH, angle DCH= angle BCD- angle BCH and angle BCH= angle ABC = 25.
DCH angle =20 degrees.
Similarly, angle CDI= = angle CDE-angle IDE, angle IDE= angle DEF, that is, angle E = 10.
Get the angle CDI = 20, so the angle DCH= angle CDI gets GH//IK.
Because AB//GH and EF//IK
So AB//EF