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A difficult problem in primary school mathematics
The number of children is 2 less than 8/ 17 of the wholesale number in the morning, and the wholesale number in the morning must be a multiple of 17: 17,34,51,68,85, 102,1/kloc. It is one of 6, 14, 22, 30, 38, 46 and 54. Because 85+38= 123 is greater than 120, the morning and morning wholesale numbers can only be:17,34,51. At this time, it can be concluded that Jingjing's wholesale count is 120- morning wholesale count-children's wholesale count is 120-23=97, 120-48=72, 120-73=47,1.