I have chemistry class.

1. Dissolve 22.4L of hydrogen chloride gas in 635.5ML of water (the density is 1g/cm 3), and the density of hydrochloric acid obtained is 1. 12g/cm 3. Calculate the content and concentration of hydrochloric acid.

2. If 500 ml 1.00 mol/L dilute sulfuric acid solution is to be prepared, what volume of 98.0% concentrated sulfuric acid (density1.80g/cm3) should be taken?

3. Calculate the amount of 36g glucose (chemical formula is C6H 12O6), the number of carbon atoms and the mass of hydrogen-containing elements.

4. The mass of a flask filled with co2 is 124.4g, the mass of o2 is 123.2g, and the mass of an unknown gas is122.8g. Find the molar mass of this unknown gas.

5. Insert a piece of zinc into a sufficient amount of H2SO4 (sulfuric acid) solution, and the quality of the solution will increase by 6.3g after the reaction. Find:

(1) The mass of zinc involved in the reaction.

(2) Volume of generated gas (under standard conditions)

(3) The quantity and quality of substances that produce ZnSO4 (zinc sulfate)

1, the amount of hydrochloric acid is 1mol, just find out the volume of the final solution.

Solution mass = water mass+gas mass =36.5+635.5=672g.

Solution volume =672/ 1. 12=600 (ml)

So the final concentration of other substances =1/0.6 =1.67 mol/L.

2. The quality of sulfuric acid in the two solutions remains unchanged.

The amount of sulfuric acid in dilute solution = 0.5l *1mol/l = 0.5mol..

So the mass of sulfuric acid =0.5*98=49g.

Set the concentrated sulfuric acid that needs Xml

So the total mass of concentrated sulfuric acid =X* 1.80.

The mass of sulfuric acid in concentrated sulfuric acid =X* 1.80*98.0%, which is the same as that in dilute sulfuric acid, that is, X* 1.80*98.0%=49.

The solution is X=27.8ml.

3,36 grams of glucose is 0.2 mole.

So the number of carbon atoms = 6 * 0.2 * 6.02 *10 23 = 7.224 *10 23.

The amount of substance of hydrogen atom = 12*0.2=2.4mol, so the mass of hydrogen element = 2.4 *1= 2.4 g.

4. O2 and CO2 differ by a c, because they are all in the same bottle, so the volume is the same and the amount of substance is the same. Use124.4-123.2 =1.2g, which is the mass of carbon element.

So the amount of carbon =1.2/12 = 0.1mol.

When 123.2- 122.8 = 0.4g, 0.4/0. 1=4, it is 4g/mol less than when oxygen is filled, so its molar mass =64-4=60g/mol.

5, Zn+H2SO4=ZnSO4+H2↑ Because the solution has increased by 6.3g, then this 6.3g= the mass of zinc-the mass of hydrogen.

Use related methods:

Zinc ~ H2

65 ~ 2

x y

So: 65/x = 2/y = 63/6.3.

It can be calculated: x = 6.5g y = 0.2g

Volume of generated gas: n = m/m = 0.2g/2g/mol = 0.1mol.

V = V(m)×n = 2.24 liters