It will take x days to complete.
Judging from the topic: a is completed every day115b is completed every day112.
The equation is:115 * x+112 * (x-7) =1.
Then solve: X= 10.5.
So it takes 1 1 day to complete.
2. The total workload of four workers in Group A in March is more than 20 pieces, which is four times the per capita quota of this month, and the total workload of five workers in Group B is six times the per capita quota of this month, which is less than 20 pieces.
(1) If the actual per capita workload of the two groups of workers is equal this month, what is the per capita quota this month?
(2) If the workers in Group A actually finish two more jobs this month than those in Group B, what is the per capita quota this month?
(3) If the per capita work actually completed by workers in Group A is 2 yuan less than that in Group B, what is the per capita quota this month?
(1) Assume that the actual per capita workload of the two groups of workers this month is X pieces, and the per capita quota this month is Y pieces.
4x=4y+20
5x=6y-20
Solution, x=50, y=45.
(2) The actual per capita workload of workers in Group A this month is X pieces, and the per capita quota this month is Y pieces.
4x=4y+20
5(x-2)=6y-20
Solution, x=40, y=35.
(3) The actual per capita workload of workers in Group A this month is X pieces, and the per capita quota this month is Y pieces.
4x=4y+20
5(x+2)=6y-20
Solution, x=60, y=55.
Group A workers in a workshop 10, including 4 women workers. There are five workers in Group B, including three women workers. First, three workers were selected from Group A and Group B by stratified sampling (simple random sampling in the layer) for technical assessment.
(i) Find out the number of people drawn from Groups A and B;
(ii) Find out the probability that there are exactly 1 female workers among the workers selected from Group A;
(Ⅰ)
Stratified sampling should be proportional, and the total number of people in group A and group B is 2: 1.
A * * * draws 3 people, group A draws 2 people, and group B draws 1 person.
If you want to make a formula, the number of people in group A =(3* 10)/ 15 = 2, and the number of people in group B =(3*5)/ 15 = 1.
(Ⅱ)
Two people were selected in Group A, and the female employees were 1, that is, male 1 and female 1.
Probability =C6 1*C4 1=24
PS: not enough. Come to me and leave a message in Baidu space.
I want to know the arrangement of the application questions of the first grade one-dimensional linear equation: tourism, engineering. Inspection of problems-> Set an unknown number->; Column equation->; Solve the equation->; Inspection->; Not a step less. Third, when the analysis conditions cannot be analyzed, read the questions sentence by sentence, and then solve them with line charts, tables and fan charts. Fourth, units should be unified.
Who can give me some questions about the application of the equation of one yuan and one time in the first day of junior high school? 1, the track of the sports ground is 400 meters long. A practice cycling, riding 350 meters per minute on average. B has practiced running, running an average of 250m per minute. They started from the same place and went back and forth at the same time. How long did it take them to meet for the first time? How long did it take to meet again?
2. A swimming pool sells summer membership cards from June to August every year. Each membership card is 80 yuan, and it is for personal use. Each admission ticket 1 yuan, each 3 yuan is not.
Q: (1) When do you buy a membership card at the same price as if you didn't?
(2) Under what circumstances is a membership card more cost-effective than not buying it?
(3) Under what circumstances is the membership card not enough than the purchase cost-effective?
3. The total length of Beijing-Shanghai Expressway is1.262km.. A car starts from Beijing, and after driving at a constant speed for 5 hours, the speed is increased by 20 kilometers per hour; After driving at a constant speed for 5 hours, the speed will decrease by10 km/h; Drive at a constant speed for another five hours and you will arrive in Shanghai.
Q: (1) Find the speed of each period. (accurate 1 km/h)
(2) Inferred from the map, where is the bus on the expressway after 8 hours?
1.(350+250)/400=6/4 (seconds)
(350+250)/400=6/4 (seconds)
Step 2 swim x times
(1) 80+x = 3x = 40 A: After 40 trips, the membership card is just like not buying it.
(2)80+X & gt； 3X & gt； Answer 40: swimming for more than 40 times, membership card is more cost-effective than not buying it.
(3)80+X & lt； 3X & lt； Answer 40: It is more cost-effective to travel less than 40 times without a membership card than to buy one.
3. Let the speed be x kilometers.
( 1)5X+5(20+X)+5(X+20- 10)= 1262
1262 = 10X+ 100+5X-50
1262= 15X-50
X=87
(2) 5 * 87+3 (87+20) = 756 (km)
A: The speed is 87 kilometers per hour, and the car travels 756 kilometers on the expressway after 8 hours.
Who can find me 30 elementary linear equations and 10 engineering problems? -2/9-7/9-56 4.6-(-3/4+ 1.6-4-3/4) 1/2+3+5/6-7/ 12 [2/3-4- 1/4*(-0.4)]/ 1/3+2 22+(-4)+(-2)+4*3 -2*8-8* 1/ 2+8/ 1/ 8 (2/3+ 1/2)/(- 1/ 12)*(- 12) (-28)/(-6+4)+(- 1) 2/(-2)+0/7-(-8)*(-2) ( 1/4-5/6+ 1/ 3+2/3)/ 1/2 18-6/(-3) *(-2) (5+3/8*8/30/(-2)-3 (-84)/2*(-3)/(-6) 1/2*(-4/ 15)/2/3 - 1+2-3+4-5+6-7 -50-28+(-24) -(-22) - 19.8-(-20.3)-(+20.2) - 10.8 0.25- +(- 1 )-(+3 ) - 1-〔 1-( 1-0.6÷3)〕×〔2-(-3)×(-4)〕 0÷(-4)-42-(-8) ÷(- 1)3 -32-(-3) 2-(-3)3+(- 1)6 3×(-2) 2+(-2×3)2+(-2+3)2 (- 12)÷4×(-6)÷2 (- 12)÷4×(-6)×2 75÷〔 138÷( 100-54) 〕 85×(95- 1440÷24) 80400-(4300+870÷ 15) 240×78÷( 154- 1 15) 1437×27+27×563 〔75-( 12+ 18)〕÷ / kloc-0/5 2 160÷〔(83-79)× 18〕 280+840÷24×5 325÷ 13×(266 -250) 85×(95- 1440÷24) 58870÷( 105+20×2) 1 437×27+27×563 8 1432÷( 13×52+78) [37.85-(7.85+6.4)] ×30 156×[( 17.7-7.2)÷3] (947-599)+76×64 36×(9 13-276÷23) -(3.4 1.25×2.4) 0.8×〔 15.5-(3.2 1 5.79) 〕 (3 1.8 3.2×4)÷5 194-64.8÷ 1.8×0.9 36.72÷4.25×9.9 3.4 1 6÷(0.0 16×35) 0.8×[( 10-6.76)÷ 1.2] ( 136+64)×(65-345÷23) (6.8-6.8×0.55) ÷8.5 0. 12× 4.8÷0. 12×4.8 (58+37) ÷(64-9×5) 8 12-700÷(9+3 1× 1 1) (3.2× 1.5+2.5)÷ 1.6 85+ 14×( 14+208÷ 26) 120-36×4÷ / kloc-0/8+35 (284+ 16)×(5 12-8208÷ 18) 9.72× 1.6- 18.305÷7
How to learn the engineering problems in the one-dimensional linear equation of junior one mathematics? I saw a web page and gave you a link. I hope it helps you.
Special Topics on the Application of One-variable Linear Equation in the First Day of Mathematics _ Baidu Library
:wenku . Baidu/link？ URL = y 8 puxapbvkxcrce 13j 5 sq 3 vora6x 08 rztvxvkzquubktzkurzzkd 8 acrqxdm 1 yuynwcgpyuedqvzjuu 3 kdybywbodokbdrx 4 cnpwp 7
The first equation engineering application exercise+answer 15. Team A and Team B complete a project in 30 days. If Team A works alone for 24 days, Team B will join the cooperation again. 12 days later, team a left because of something, and team b continued to do it 15 days.
Analysis: A does it for 24 days first, and B does it for 15 days last, which can be understood as 15 days plus 12 days first, and * * * does it for 27 days. =90 days
2. A project can be completed by teams A and B every day. Team A can finish the whole project in three days, and team B can finish it in five days. If the whole project is done by team B alone, how many days can it be completed?
It can be understood that the two teams worked together for three days. = 10 (days)
3. Group A and Group B cooperate to complete a project within 20 days. If two teams work together for 8 days, team B will work alone for 4 days and leave the project. How many days does it take for Team A and Team B to finish alone?
B's work efficiency =
B Days required: 1÷=60 (days)
Days required by Party A and Party B: 1÷=30 (days)
4. Team A/KLOC can finish a project in 0/0 day, while Team B can finish it in 30 days. Now, during the cooperation between the two teams, Team A has rested for 2 days, while Team B has rested for 8 days (the two teams don't rest on the same day). How many days did it take from the beginning to the end?
Analysis: It can be understood that A works 6 days more. +8= 1 1 (days).
A project can be completed in 6 days if Team A does it alone. It takes 3 days for Team A to work and 4 days for Team B to finish. After two days of joint work, team B will finish it alone. How many days does team b need to finish?
Work efficiency of A and work efficiency of B =3 (days)
6. A highway will be built in 0/5 days for Team A and 0/2 days for Team B.. After four days of joint repair, team B was moved and the remaining route A continued to be completed. How many days did Team A finish?
Answer: 10 (days)
7. A project will be completed in 20 days by Party A and 30 days by Party B.. After several days, Party A and Party B asked for leave because of something, and Party A continued to do it. It took 65,438+06 days from the beginning to the completion of the task. How many days off did Party B take?
Answer: 10 (days)
8. It takes 12 days for Party A and Party B to build a road together, and now it takes 3 days for Team A to build it, and then it takes 1 day for Team B to build it. If this expressway is repaired by Team A alone, how many days will it take to be completed?
Answer: 120 (days)
9. Two trains leave from A and B at the same time. It takes 20 hours for the express train to complete the journey, and 30 hours for the local train to complete the journey. The two trains met 15 hours after departure. It is known that the express train stops for 4 hours and the local train stops for several hours.
Answer: 2 hours
10, the master and the apprentice processed a batch of parts together, and the total number was processed in two days. If all these parts are processed by the master alone, it will take 10 days to complete. How many days will it take if all of them are processed by apprentices?
Answer: 15 (days)
11:Team A and Team B dig canals. It takes 8 days for Team A to dig alone, and it takes 12 days for Team B to dig alone. Now, after two teams dig at the same time for a few days, team B will be transferred and the remaining team A will be completed in three days. Bravo team dug for a few days.
Solution: It can be understood that Team A will do it first, and the two teams will dig together three days later. =3 days
12: Processing a batch of parts can be completed in 20 days by Party A and 30 days by Party B. Now the two teams cooperate to complete this task. During the cooperation, Party A has a rest of 2 .5 days and Party B has a rest of several days, so *** 14 days will be completed. Party B has a few days off.
Solution: analysis: * * * 14 days to complete, that is, Party A does (14-2.5) days, and the rest is done by Party B. The number of days that Party B does minus14 days is the number of days that Party B takes a rest.14 =1.
13: A pool of water, in which pipe A and pipe B are opened at the same time and filled in 5 hours, and pipe B and pipe C are opened at the same time and filled in 4 hours. Now it takes 6 hours to open the B tube first, and 2 hours to fill both the A tube and the C tube. If you drive B alone, it will be full in a few hours.
Solution: Analysis: If Party B starts 6 hours, it will be regarded as 2 hours with Party A, 2 hours with Party C, and there are 2 hours left. Now it can be understood as 2 hours with Party A, 2 hours with Party B, and the rest is 2 hours with Party B, 1÷=20 (hours).
14: With the cooperation of both parties, a project can be completed in 1 day. If team A works for 2 days and team B works for 3 days, it can be completed. How many days does it take for Team A and Team B to complete the project alone?
Solution: Analysis: It can be understood that two teams worked together for 2 days, and the rest was completed by B within 1 day. B's ergonomics is A: = 12 (days).
15: For a project, Party A works alone for 2 days, and then works with Party B for 7 days, so the whole project is half finished. As we all know, the efficiency ratio of Party A and Party B is 2:3. If this project is completed by Party B alone, how many days will it take?
Solution: Analysis: The working efficiency of B is 3 ÷ 2 = 65438+0.5 times that of A, the working efficiency of A is X, and the working efficiency of B is1.5x.,
(2+7)x+ 1.5x×7=, the solution is: x=, ergonomics 1÷ 1.5x =26 (days).
Give an example of a simple linear equation engineering problem. : A's work can be completed in 10 day, and B 15 day. How many days can two people cooperate to complete it?
As a whole, an assignment is 1, so the workload can be counted as 1. The so-called work efficiency is the amount of work completed in a unit time. The time unit we use is "day", and 1 day is a unit.
According to the basic quantitative relationship, we get
Time required = workload/work efficiency
=6 (days)?
It takes six days for two people to cooperate.
This is the most basic problem in engineering, and many examples introduced in this lecture are developed from this problem.
In order to calculate integers (as far as possible), the workload is divided into more shares like the third example 3 and example 8. Again, the least common multiple of 10 and 15 is 30. Assume that the total workload is 30 copies. Then Party A will complete 3 copies every day and Party B will complete 2 copies every day. How many days does it take for two people to cooperate?
30(3+2)= 6 (days)
It is more convenient to calculate the numbers.
: 2. Or "the workload is fixed, and the work efficiency is inversely proportional to the time". The work efficiency ratio of Party A and Party B is 15: 10 = 3: 2. When the working efficiency ratio of the two is known, consider the problem from the perspective of proportion, and also
The required time is
Therefore, in the description of the following examples, we do not completely adopt the practice of "setting the workload as a whole 1" in the usual textbooks, but focus on "integers" or "from the perspective of proportion", which may make our thinking of solving problems more flexible.
First, the problem of two people.
The two people mentioned in the title can also be two groups, two teams and so on.
Example 1 A can finish the work in 9 days, and B can finish the work in 6 days. Now A has done it for three days first, and B continues to finish the rest. B How many days does it take to finish all the work?
Answer: B It takes 4 days to finish all the work.
Scheme 2: The least common multiple of 9 and 6 is 18. Let the total workload be 18. Party A completes 2 copies every day, and Party B completes 3 copies every day. How long does it take Party B to complete the remaining work?
(18- 2 × 3)÷ 3= 4 (days).
Solution 3: The ratio of working efficiency of A and B.
6∶ 9= 2∶ 3.
A has done 3 days, which is equivalent to 2 days for B. It takes 6-2=4 (days) for B to finish the rest of the work.
With the cooperation of both parties, a job can be completed in 30 days. After 6 days, Party A left and Party B continued to do it for 40 days. If this work is done by Party A or Party B alone, how many days will it take?
Solution: * * * did it for 6 days.
It turns out that A does it for 24 days and B does it for 24 days.
Now, A does 0 days and B does 40=(24+ 16) days.
This shows that the work that A did in 24 days can be replaced by B in 16 days, so the work efficiency of A is high.
If b does it alone, the time required is
If A does it alone, the time required is
Answer: It takes 75 days for A to do it alone, or 50 days for B to do it alone.
A project can be completed by Party A alone for 63 days, and then by Party B alone for 28 days. If both parties cooperate, it will take 48 days to complete. Now Party A does it alone for 42 days, and then Party B does it alone. How many more days does Party B need to do?
Solution: First, compare the following:
63 days for A and 28 days for B;
A does it for 48 days and B does it for 48 days.
It is known that A needs to do 63-48= 15 (days) less, and B needs to do 48-28=20 (days) more, thus obtaining A's.
A has been doing it for 42 days, and 63-42=2 1 (day) is less than 63 days, which is equivalent to B.
So, B still has to do it.
28+28= 56 (days).
A: B It will take another 56 days.
Example 4 A project was completed by group A alone 10 day, and group B alone for 30 days. Now the two teams cooperate, during which Team A has a rest for 2 days and Team B has a rest for 8 days (neither team has a day off). How many days did it take from the beginning to the end?
Scheme 1: Team A works alone for 8 days and Team B works alone for 2 days, thus completing the workload.
The remaining workload is the cooperation between the two teams. How many days will it take?
2+8+ 1= 1 1 (days).
Answer: It took 1 1 day from the beginning to the end.
Solution 2: We assume that the total workload is 30 copies. Party A completes 3 copies every day, and Party B completes 1 copy every day. Team A works alone for 8 days, and after team B works alone for 2 days, the two teams need to cooperate.
(30-3× 8-/kloc-0 /× 2) ÷ (3+1) =1(days).
Option 3: Team A does 1 day, which is equivalent to Team B doing 3 days.
After team A did it alone for 8 days, there was still (team A) 10-8= 2 (days) workload, which was equivalent to team B's 2×3=6 (days). After doing it alone for 2 days, there was still (team B) 6-2=4 (days) workload.
4=3+ 1,
Three days can be completed by team A 1 day, so the two teams only need to cooperate 1 day.
Example 5 A project is completed by Team A in 20 days and Team B in 30 days. Now they are working together, during which Team A has a rest for 3 days and Team B has a rest for a few days. It took 16 days from start to finish. How many days did Team B rest?
Option 1: What if both teams don't rest for 16 days?
Because the workload that the two teams didn't do during the break was
The amount of work that team B didn't finish during the break was
How many days will Team B rest?
A: Team B rested for five and a half days.
Solution 2: Assume that the total workload is 60. Party A completes 3 copies every day, and Party B completes 2 copies every day.
The workload that the two teams didn't do during the break was
(3+2)× 16- 60= 20 (copies).
Therefore, B's rest day is
(20- 3 × 3)÷ 2= 5.5 (days).
Option 3: Team A does it for 2 days, which is equivalent to Team B doing it for 3 days.
Team A has a 3-day rest, which is equivalent to 4.5 days rest for Team B. 。
If Team A 16 doesn't rest, Team A will only work for 4 days, which is equivalent to 6 days for Team B. Team B's rest day is
16-6-4.5=5.5 (days).
Example 6 has two tasks, A and B. It takes 65,438+00 days for Zhang to complete task A alone, and 65,438+05 days for Zhang to complete task B alone. It takes 8 days for Li to complete work A and 20 days for Li to complete work B. If two people can cooperate in each job, how many days will it take to complete these two jobs?
Solution: Obviously, Li's work efficiency in doing A work is high, and Zhang's work efficiency in doing B work is also high. So let Li do A first and Zhang do B first.
Suppose B's workload is 60 copies (15 and the least common multiple of 20), Zhang completes 4 copies every day and Li completes 3 copies every day.
In another 8 days, Li will be able to finish work A. At this time, Zhang still has (60-4×8) copies of work B, which needs the cooperation of Zhang and Li.
(60-4×8)÷(4+3)=4 (days).
8+4= 12 (days).
A: It will take at least 12 days to complete these two tasks.
For a project, it takes 10 days for Party A to do it alone, and 15 days for Party B to do it alone. If two people cooperate, they will.
It takes eight days to complete the project, and the fewer days two people work together, the better. So how many days do two people work together?
Solution: Assume that the workload of this project is 30 copies, with Party A completing 3 copies every day and Party B completing 2 copies every day.
Two people cooperate, * * * to complete.
3× 0.8+2 × 0.9= 4.2 (copies).
Because two people should work together for as few days as possible, the one who works alone should be the one with high efficiency. Because it will be completed in 8 days, the number of days for two people to cooperate is
(30-3×8)÷(4.2-3)=5 (days)
Obviously, it finally became a problem of "chickens and rabbits in the same cage".
Example 8 Party A and Party B cooperate in a job. Because of their good cooperation, Party A's work efficiency is faster than when doing it alone.
How many hours will it take if this work is always done by one person alone?
Solution: what is the workload of B working alone for 6 hours?
B the workload per hour is
Two people work together for 6 hours. What does A accomplish?
A the amount of work done per hour when working alone
A How long does it take a person to do this job?
A:A It takes 33 hours for one person to finish the work.
Most examples in this section are treated as "integers". However, "integer" does not make the calculation of all engineering problems simple. This is the case in Example 8. Example 8 can also be an integer, when b is found.
It's convenient, but it doesn't do much good. There is no need to reinvent the wheel.
Second, many people's engineering problems.
When we talk about many people, there are at least three. Of course, the multi-person problem is more complicated than the two-person problem, but the basic idea of solving the problem is still similar.
Example 9 A job is completed in 36 days by Party A and Party B, 45 days by Party B and 60 days by Party A and Party C. How many days does it take for Party A to complete it alone?
Solution: Let the workload of this work be 1.
The cooperation among Party A, Party B and Party C is completed every day.
Minus the work done by Party B and Party C every day, Party A will finish it every day.
A:A It takes 90 days to do it alone.
Example 9 can also be rounded off, assuming that the total workload is 180, Party A and Party B complete 5 copies per day, Party B and Party C complete 4 copies per day, and Party A and Party C complete 3 copies per day. Please have a try. Will it be more convenient to calculate?
Example 10 for a job, it takes 12 days for A to do it alone, 18 days for B to do it alone, and 24 days for C to do it alone. The work was done by A for a few days, then by B for three times as many days as A, and then by C for twice as many days as B, and finally the work was completed.
Solution: A does 1 day, B does 3 days, and C does 3×2=6 (days).
Explain that A did it for 2 days, B did it for 2×3=6 (days), C did it for 2×6= 12 (days), and three people did it together.
2+6+ 12=20 (days).
It took 20 days to finish the work.
The integer of this problem will bring convenience to the calculation. There is an easy-to-find minimum common multiple 12,18,24. 72. It can be assumed that the total workload is 72. A completes 6 every day, B completes 4 and C completes 3. The total workload is * * *.
Example: 1 1 A project needs the cooperation of Party A, Party B and Party C 13 days. If Party C asks for two days off, Party B has to do four more days, or both parties cooperate 1 day. How many days will it take for this project to be completed by Party A alone?
Solution: Two days' work of Party C is equivalent to four days' work of Party B, and the work efficiency of Party C is 4÷2=2 (times) that of Party B, and the cooperation between Party A and Party B 1 day is the same as that of Party B's four days. In other words, Party A works 1 day, which is equivalent to Party B's working for 3 days, and Party A's working efficiency is 3 times that of Party B. 。
They worked together for 13 days, which was done by Party A alone and needed by Party A..
A:A It takes 26 days to do it alone.
In fact, when we calculate the working efficiency ratio of Party A, Party B and Party C as 3∶2∶ 1, we know that Party A works 1 day, which is equivalent to the cooperation of Party B and Party C 1 day, and the cooperation of three people takes 13 days, and the workload completed by both parties can be converted into Party A.
Example 12 For a certain job, three people in Group A can finish the job in eight days, and four people in Group B can finish the job in seven days. How long will it take two people in group A and seven people in group B to finish the work together?
Scheme 1: Let the workload of this work be 1.
Everyone in group a can finish it every day.
Everyone in group b can finish it every day.
Two people in group A and seven people in group B can finish it every day.
A: The work can be completed in three days.
Scheme 2: 3 people in group A can finish it in 8 days, then 2 people can finish it in 12 days; Four people in group B can finish it in seven days, so seven people can finish it in four days.
Now, regardless of the number, the question becomes:
Group a worked alone 12 days, while group b worked alone for 4 days. How many days will the cooperation be completed?
Elementary school arithmetic should make full use of the particularity of given data. Scheme 2 is a typical example of flexible use of proportion. If you do your mental arithmetic well, you will get the answer soon.
Example 13 it takes 10 days for workshop a to make a batch of parts, but it only takes 6 days if workshop a and workshop b do it together. Workshop b and workshop c work together, which takes 8 days to complete. Now three workshops are working together, and it is found that workshop A has made 2400 more parts than workshop B. How many parts has workshop C made?
Scheme 1: Let the total workload be 1.
A finishes more than B every day.
So the total number of these parts is
The number of parts produced in Workshop C is
A: Workshop C has produced 4200 parts.
One-dimensional linear equation-engineering problem (full) 1. Party A will complete a project within 25 days, and Party B will complete it within 35 days ... At present, Party A will do it for a few days first, and then Party B will join the joint venture. However, after Party B joined, Party A only worked for half a day, so it was completed 22 days after Party A started working. A did it for a few days? B did it for a few days?
2. A project can be completed by team A and team B in 20 days, and team A can be completed by one person in 30 days. Now 15 days later, how many days will Team A need to finish the rest?
Team A and Team B can complete a project in 8 days. If Team A works alone for 6 days, the rest of the work can only be completed by Team B 12 days. Q: How many days will it take for Team A and Team B to finish this project alone?
4. Project A can be completed by one person in 50 days, and Project B can be completed by one person in 75 days. Now they are working together, but on the way, B walked for a few days because of something, and finally it took 40 days to finish the project. So how many days did B walk?
5. For a project, Party A works alone for 36 days, and Party B works alone for 45 days. If Team A and Team B work together at the start of construction and Team A quits to start a new project, then Team B will need 18 days to complete the task. Q: How many days did Team A work?
Ask an application question of the trip problem of the first two-dimensional linear equations in junior high school. Party A and Party B run at a constant speed on the circular road and walk in opposite directions, meeting once every two minutes and walking in the same direction, and meeting once every six minutes. It is known that Party A runs faster than Party B, so how many laps does Party A run per minute?
Solution: Assume that Party A and Party B run X and Y laps every minute, and the length of this lap is Z.
2x+2y=z
6x-6y=z
Get a solution
x=z/3，y=z/6
Then A runs 1/3 laps per minute, and B runs 1/6 laps per minute.
How to write the application problem of one yuan linear equation in the first day of junior high school? Solution: Set. . . . . . . . Is x (unit)
According to the meaning of the question, yes. . . . . . . (listed equations)
. . . . . . . . . . . . . . . (process)
x= .。 . . . (Answer, no unit)
A: Yes. . . . . . . . .