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Mathematical problems in primary schools
Analysis:

"Divide by 9 she8, divide by 8 she7, divide by 7 she6, divide by 6 she5, divide by 5 she4, divide by 4 she3, divide by 3 she2, divide by 2 she 1, divide by 8 minus 1 and divide by 7 minus/kloc-0".

Divided by 9, divided by 8, divided by 7, divided by 6, divided by 5, divided by 4, divided by 3, divided by 2 are all 1 less.

If the division of 9, 8, 7, 6, 5, 4, 3 and 2 can be divided, then the minimum number should be

Least common multiple of 9, 8, 7, 6, 5, 4, 3 and 2-15 120

To make sure it is

Six digits

, put

15 120 is expanded into six digits, that is,15120× 7 =105840.

Because it is inseparable, it is still missing 1, so it is still used.

105840- 1= 105839

Process:

= 15 120

15 120×7= 105840

105840- 1= 105839

A: This number is 105839.