So 0 = a? b？ 35= 16a+4b？ 3,

A = 1b =？ 2,

The expression of parabola is y=x2-2x-3.

The symmetry axis is a straight line x= 1,

According to the meaning of the question, if the analytical formula of straight line BC is y=kx-3, then 5=4k-3 and k=2,

The analytical formula of line BC is y=2x-3,

∴p( 1,- 1)；

(2) Move parabola ① to the right by 1 unit, and then move it up by m units to get parabola ②.

The expression of parabola ② is y=(x- 1- 1)2-4+m,

∵ parabola ② passes through point P,

∴- 1=( 1- 1- 1)2-4+m，

∴m=2，

∴ Move it up by 2 units to get a parabola ②;

(3)∵ Parabola ① moves to the right by 1 unit, and then moves up by 2 units to get parabola ②,

The expression of parabola ② is y=(x- 1- 1)2-4+2, that is, y=(x-2)2-2.

∴D(2,-2),E(0,2)，

∫P( 1，- 1)，

∴ The straight line DP passes through the point O, and the included angle with the X axis is 45.

After passing through point e, it becomes EH⊥DP at point h,

∴∠EOH=45，

∫E(0，2)，

Eh = 2，ED=22+(2+2)2=25，

∴sin∠EDP=EHDE