Yes, your question is relatively simple, and I didn't use set to do it. The code is as follows.

min = 10 * t 1 * p 1+9.9 * T2 * p2+9.8 * T3 * P3+ 1 1.3 * T4 * P4；

p2+P3 = 1；

p 1 = 1；

p2 = 1；

@bnd(2，t 1，6)；

@bnd(2，t2，8)；

@bnd(2，t3，5)；

@bnd(2，t4，6)；

@ bin(p 1)；

@ bin(p2)；

@ bin(P3)；

@ bin(P4)；

The result is 39.8, where T 1 = T2 = T3 = T4 = 2, P 1 = P2 = 1, P3 = P4 = 0.