Solution:1) ∵+0.0018 │ < 0.002, │-0.0023 │ > 0.002 │+0.0025 │ > 0.002, │-0.0015 │.

│ +0.00 12 ││+0.00 18 │

> │-0.00 15│ >│+0.00 12│ >│+0.00 10│

+∴+0.00 10/0 The net content of this bottle is the closest to the specified net content.