1. If ducks are regarded as 1 and there are four chickens, then 135 is three times that of ducks, so ducks are 135÷(4- 1)=45 (only) and chickens are 45+655. This is a "differential multiple problem", and the differential multiple difference = decimal.

2. If the pear is regarded as 1, and there are 8 apples, then the box of 128 is 9 times that of the pear, so the pear is128 ÷ (1+8) =128/9 (box), 60. This is a "problem of sum and multiple", and the sum of multiple is equal to decimal. By the way, is 128 misspelled? )

3. Because dividend = divisor× quotient+remainder, dividend can be written as "divisor× 8+1"according to known conditions. And because dividend+divisor+quotient+remainder = 1 18, then (divisor ×8+ 1)+ divisor +8+ 1 = 18, so divisor = (65438

According to the known conditions, the price of two basketballs is 200 yuan. The formula (570-370)÷(5-3)= 100 (yuan).

5. "The number of zeros in the digits of A is equal to the number of B" means "The number of A is 10 times that of B", and the method of this question is the same as that of the second question. Then the number b is 253÷( 10+ 1)=23, so the number a is 23× 10=230.

6. "What's left is just equal to the weight of the original two boxes" means "what's poured is just equal to the weight of the original six boxes", so the original average weight of each box is 15×8÷(8-2)=20 (kg).

7. The method of solving the problem is the same as the second question: longan tree: 480÷( 1+3)= 120 (tree), mango tree: 120×3=360 (tree).

8. If another factor is not wrong, the wrong result is actually (2 1- 12) times less than the correct result, and the factor that is not wrong is1107 \ (21-kloc-0/2).