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Mathematics examination questions (seeking process)
Solution: Connect AE

∫BE is the diameter of the circle o.

∴∠BAE=90

∵AB⊥CD

∴AE∥CD

∴ Quadrilateral AECD is a trapezoid.

∫ arc AE= arc AE

∴∠ACD=∠ADC

∴ Trapezoidal AECD is an isosceles trapezoid.

∴AC=ED

AC = 3

∴DE=3