∠EBC = 180-∠ABC∠BCF = 180-∠BCF

So ∠ EBC+∠ BCF = 360-(∠ ABC+? ∠BCF)

And BP and CP are the bisectors of ∠EBC and ∠BCF.

So what? ∠PBC +？ ∠PCB =( 1/2)(∠EBC +？ ∠BCB)？

=( 1/2) * [ 360 - (∠ABC +？ ∠BCF)

? = 180 - ( 1/2)(∠ABC +？ ∠BCF)

? = 180 - ( 1/2) * 1 16 = 122

So what? ∠P = 180-(∠PBC-∠PCB)= 180- 122 = 58

Therefore, your answer is correct.