Analysis: The balls in this question are exactly the same, so there is no difference. The problem is equivalent to dividing the ball into three groups, allowing several groups without elements, and using the partition method.

Dividing eight balls into three groups requires two partitions, because allowing the box to be empty does not conform to the principle of partition method. Then three balls are artificially added to ensure that at least one ball is allocated to each box, which meets the requirements of zoning method (one ball is removed from each group after zoning, which meets the requirements of topic setting).

So the problem becomes that the total number of balls to be divided is 1 1, and there are 10 gaps in the middle of the balls. It is necessary to add two separators at the gap of 10 to divide them into three parts, that is, there are 45 different methods for C (10/0,2).