The last number is 8 larger than the next one.

If you take the fifth column as the benchmark. The rows where the numbers appear in the fifth column are arranged from large to small. this way

Have-5-8x; 95/8, take the smallest integer greater than 95/8 12 and substitute -5-8X=- 10 1, then

On the horizontal line where-10 1 appears, the number on the left is-100, and the corresponding column is the fourth column.

Similarly, based on the column 1, the same result is obtained, but the equation used is-9 -9-8x >；; -100. Because the numbers in the 1 column are arranged from small to large. The solution is x < 9 1/8, the largest integer less than 9 1/8 is 1 1, and the number of the 1 column here is -97. Then according to the pattern in the title, we can also find that-100 is in the fourth column.

So-100 is in the fourth column.