Current location - Training Enrollment Network - Mathematics courses - The following is the emblem of the International Congress of Mathematicians held in Beijing in August 2002. It consists of four identical right-angled triangles and a big square in the middle.
The following is the emblem of the International Congress of Mathematicians held in Beijing in August 2002. It consists of four identical right-angled triangles and a big square in the middle.
As shown on the right,

Let two right angles of a large right triangle be A and B (A > B) and the hypotenuse be C,

Then a 2 +b 2 =c 2,

∴a 2 +b 2 = 13 2,

∫a-b = 7,

∴a=7+b,

∴(7+b) 2 +b 2 = 169

The solution is b=5 (negative numbers are rounded off).

So the answer is 5.