∵AE⊥BE,BM∩BE=B

∴AE⊥ face BCE

BC? Facial BCE

∴ae⊥bc；

(2) Solution: Take the midpoint p of DE and connect PM and AP.

∵BC=BE,BM⊥AE

∴M is the midpoint of the Chief Executive.

∴MP∥ 12DC∥AN

∴AMNP is a parallelogram

∴MN∥AP

∵MN？ Facing Ade, AP? frontage

∴MN∥ Surface appearance

(3) Solution: BC⊥BE is obtained from BE=BC=4 and CE=42.

∵BC⊥AE,AE∩BE=E

∴BC⊥ Noodles Abe

∴∠ABE is the plane angle of dihedral angle A-BC-E.

∴∠ABE=45

∴AE=BE=4.

Let a point p satisfy the meaning of the question, PQ⊥AE is in Q, then ∠PBQ is the angle formed by BP and plane ABE.

Let QE=x, because △ADE is an isosceles triangle, then [Q=x, PE=2x.

In the right angle △BQE, BQ=x2+ 16, in the right angle △PQB, tan 30 = xx2+ 16 = 33.

X = 22, so when PE=4, the angle between BP and plane ABE is 30.