Then a+b+c=44 (1)
2a+3b+4c= 14 1 (2)
2b- 1=c (3)
Substituting (3) into (1) and (2) gives:
a+3b=45 = >2a+6b=90(4)
2a+ 1 1b= 145 (5)
Subtract formula (4) from formula (5): 5b = 55b =11.
Then c=2 1 and a= 12, then the number of bicycles is 12.
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