For example:
1: When n approaches infinity, [1/N2+1(n+1) 2+1/(n+2) 2+...+1.
2. When n approaches infinity, [1(N2+pie)+1(N2+pie)+...+1(N2+pie).
3:lim sinx (n approaches 0) limit, it is better to list the calculation steps of this limit.
I know the answers to the above three questions, but I don't know the calculation process. I don't know how the answer came from.
The limit of the problem sinx (when x approaches 0).
Best answer
1、0 & lt 1/n^2 < 1/n * 1/(n+ 1)= 1/n- 1/(n+ 1)
2、n( 1/n^2)= 1/n & gt； 1/(n 2+ faction)+1(n 2+2 faction) +...+ 1/(n 2+n faction) > 0
Pinch theorem (pinch theorem)
3. What's your question?
3. sinx = 0 when x = 0, and then it can be obtained from the continuity of sinx.
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