y = | x & amp# 178; - 1|/(x- 1)

①x & gt； 1 or x≤- 1, y = (x & # 178; - 1)/(x- 1)= x+ 1

②- 1 & lt； x & lt 1，y =( 1-x & amp； # 178; )/(x- 1)=-(x+ 1)

The image with y=kx-2 is a straight line passing through (0, -2).

Let C(0, -2)

The dotted line in the figure shows two extreme cases, k(CA)=4.

The slope of the blue line is 1.

To use an image, there must be two intersections, and the value range of k is (0, 1)U( 1, 4).

Shit, is it cheating or NC this time?